x[i]=x[3-i]+2

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Solution for x[i]=x[3-i]+2 equation:


Simplifying
x[i] = x[3 + -1i] + 2

Multiply x * i
ix = x[3 + -1i] + 2
ix = [3 * x + -1i * x] + 2

Reorder the terms:
ix = [-1ix + 3x] + 2
ix = [-1ix + 3x] + 2

Reorder the terms:
ix = 2 + -1ix + 3x

Solving
ix = 2 + -1ix + 3x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'ix' to each side of the equation.
ix + ix = 2 + -1ix + ix + 3x

Combine like terms: ix + ix = 2ix
2ix = 2 + -1ix + ix + 3x

Combine like terms: -1ix + ix = 0
2ix = 2 + 0 + 3x
2ix = 2 + 3x

Divide each side by '2x'.
i = x-1 + 1.5

Simplifying
i = x-1 + 1.5

Reorder the terms:
i = 1.5 + x-1

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